1 Find the probability that three students A, B, and C are in the same cafeteria

1 Each student's choice is random, the probability of choosing any one of the canteens is 1 2 three students, and the probability of choosing a canteen at the same time is (1 2) 3 = 1 8 and because there are 2 canteens, the probability of being in the same cafeteria = 2 8 = 1 42 First calculate the probability that all three students are not eating in restaurant B, that is, all three of them are in restaurant A, so the probability is (1 2) 3=1 8

Then subtract the probability that all three students did not eat in restaurant B by 1, which is the probability that at least one person will eat in restaurant B.

1 2/(2*2*2)=1/4

Question 1: Three students can eat in the same cafeteria in A or B, so there are two types, and each of the three students can choose A or B, so it is 2*2*2 situation, and Question 2 All three students do not eat in B, that is, they all eat in A, and the probability of this is 1 8

1-1 8 is the probability that at least one person will eat at restaurant B.

Simple: (1): 1 4(2): 7 8

The choice of students A, B, and C is nothing more than a choice of two or the other; But for three people to get together, they must: 1 2 * 1 2 * 1 2 * 2 = 1 4

2 is because there are two restaurants!