There is a two story cafeteria, and three students, A, B, and C, each choose one of them at random

Updated on Restaurant 2024-03-11
3 answers
  1. Anonymous users2024-01-23

    There are two floors of A and B, and there are 8 situations in total

    A, A, B, A, B, A, B

    C A B A B A B A B A B

    There are 2 situations on the first floor, and the probability = the ratio of the number of situations sought to the total number of situations, so the probability of A, B and C eating on the same floor is 2 8 1 4.

  2. Anonymous users2024-01-22

    A1B1C1 A2B1C1

    A1B1C2 A2B1C2

    A1B2C1 A2B2C1

    A1B2C2 A2B2C2C2

    So it's 1 4

  3. Anonymous users2024-01-21

    It should be 1 4, suppose A chooses a restaurant randomly, the probability of A and B going to the same restaurant is 1 in 2, and the probability of A and C in the same restaurant is also 1 in 2, multiplied, so the probability of the same restaurant is 1 in 4.

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