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The following is the duration calculation.
The time required for two old people is 1 2 * 40 days = 20 days, and the time required for four apprentices is 1 4 * 40 days = 20 days, the above are the working hours of separate production, but the production efficiency of the old man is twice that of the apprentices, 20 2 = 10 days.
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It's OK to do it for ten days, and the formula is [(1 40)*2+(1 80)*4]*X=1
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According to the theoretical algorithm: 1 (2*1 40+4*1 80)=10 days.
1 All 1 (1 40 + 1 80) = 1 (3 80) = 80 3 =
I guess it's 5 days.
Regardless of the actual situation, from a mathematical point of view: according to the topic, the labor efficiency of four apprentices is equivalent to that of two old workers, then the labor efficiency of two old workers and four apprentices is four times that of one old worker, so the labor time is 1 4 of that of an old worker, and the answer is 30 4 = days to complete.
1 (1 30*2+1 60*4) = days.
That is, the day can be completed the fastest. >>>More
The workload of four apprentices is equal to that of two old people, so it is equivalent to four old people doing, then it is 30 divided by 4 equal to the day can be completed.