A set of furniture that is completed in 40 days by an old worker and 80 days by an apprentice.

Updated on furniture 2024-08-07
3 answers
  1. Anonymous users2024-01-24

    The following is the duration calculation.

    The time required for two old people is 1 2 * 40 days = 20 days, and the time required for four apprentices is 1 4 * 40 days = 20 days, the above are the working hours of separate production, but the production efficiency of the old man is twice that of the apprentices, 20 2 = 10 days.

  2. Anonymous users2024-01-23

    It's OK to do it for ten days, and the formula is [(1 40)*2+(1 80)*4]*X=1

  3. Anonymous users2024-01-22

    According to the theoretical algorithm: 1 (2*1 40+4*1 80)=10 days.

Related questions
3 answers2024-08-07

1 All 1 (1 40 + 1 80) = 1 (3 80) = 80 3 =

4 answers2024-08-07

Regardless of the actual situation, from a mathematical point of view: according to the topic, the labor efficiency of four apprentices is equivalent to that of two old workers, then the labor efficiency of two old workers and four apprentices is four times that of one old worker, so the labor time is 1 4 of that of an old worker, and the answer is 30 4 = days to complete.

2 answers2024-08-07

1 (1 30*2+1 60*4) = days.

That is, the day can be completed the fastest. >>>More

1 answers2024-08-07

The workload of four apprentices is equal to that of two old people, so it is equivalent to four old people doing, then it is 30 divided by 4 equal to the day can be completed.