The school cafeteria serves a set menu for 1,000 students every day, with two sets A and B every Mon

Updated on Restaurant 2024-10-02
2 answers
  1. Anonymous users2024-01-24

    a(n+1)=

    bn=1000-an

    So a(n+1)=

    a(n+1)-600=

    So it's a proportional series.

    an-600=(a-600)*(1 2) n, so an=(a-600)*(1 2) n+600

  2. Anonymous users2024-01-23

    Solution:( A(n+1) is represented by an and bn

    a(n+1)=an*80%+bn*30%

    Try to determine the relationship between an and a(n+1) and find the general term anbn=1000-an when a1=a

    a(n+1)=an*80%+(1000-an)*30%=an*50%+300

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