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Anonymous users2024-01-241. The altitude drops by 10m, so the work done by gravity W(G)=mgh=2*10*10=200J
2. Apply the kinetic energy theorem: v=15 m s
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Anonymous users2024-01-23The work done by gravity is mgh=200N
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Anonymous users2024-01-221.The gravitational workmanship is, Wg=
2.The kinetic energy at the time of landing is, Ek=Ek0+Wg=(1 2)X2X5 2+196=221J
So the velocity is v=(EkX2 m) (1 2)=
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Anonymous users2024-01-21w=mgh=2*10*10=200 J
Q2=W+Q1=200+ Vt=15 m/s
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Anonymous users2024-01-20The work done by gravity is mgh=200J, 1 2mv 2+mgh=1 2mv(end) 2, and the final velocity is 15ms
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