What is the size of the float pool for automatic flushing in public toilets

Updated on Toilets 2024-08-01
1 answers
  1. Anonymous users2024-01-24

    [Problem solving ideas and methods].

    This is a comprehensive problem that uses pressure, buoyancy and other knowledge to solve practical problems, involving many physical formulas and physical processes. For such problems, students should not be in a hurry to solve them, but first analyze the physical process according to the required quantities and known quantities, form solutions to the problems, and then make specific calculations.

    Analysis method: the depth of water in the tank is required, according to Figure 21, the length of the thin wire is known, the thickness of the valve C, and the depth of the pontoon B in the water is known again. The depth of pontoon B in the water is determined by the force it is subjected to.

    Perform a force analysis on the buoy B: subject to the upward buoyancy force, the downward gravity, the downward pull force of the valve on it. Because B is stationary, there is:

    F float = GB+ F pull, according to Archimedes' principle, F float contains the volume of B in the water, that is, the depth in the water, but the size of F pull is not known.

    Perform a force analysis on valve C: subject to upward tension and downward pressure. Because C is at rest, there is: F pull = F pressure.

    The tensile force of C is equal to the tensile force of C to B, and F pressure = PSC , P = (h+l)g

    At this point, the students can see that the depth of B in the water can be found by using F float = GB+ F pull, and then the depth of the water in the tank.

    Reference answer] Let the depth of float B immersed in water be h when valve C is just opened.

    F float = GB+F pull.

    F-pull = F-pressure.

    Because F-pull = F-pull.

    So F float = GB + F pressure.

    Water gSBh = mBg + water gSC (h + l).

    Bring in the data to solve: h = 30cm

    Then the water depth is: H=h+ l+d

    30cm+10cm+=

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