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This is an arithmetic problem to find the common divisor, the greatest common divisor of 60 and 48 is 12, which is not in the value given in the question, and the lower common divisor is 6, in the value given, so the answer is a floor tile with a side length of 6 decimeters.
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A common multiple of 60 and 48 will do! Both 6*6 and 8*8 are available! The maximum multiple is 12, so the maximum choice is 12*12 bricks.
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Regardless of the size of the loss, how big and how big it can be used! i.e. 9*9 floor tiles! If the loss is counted, the 8*8 floor tile has the smallest loss, with a total of 48 pieces.
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Choose 6 6 floor tiles for a total of 80 tiles.
Available in 30x30, 40x40, 60x60. 80x80 should not be used because it needs to be cut.
Question 1: What are the units of 30*30, 40*40, 60*60, 80*80? Centimeters (cm)? >>>More
You make it X
X square 80 blocks = 20 square meters. >>>More
I am a kitchen designer.
Personally, I don't think either size is very good. >>>More
Description: The floor is relatively thin! There is a risk of water leakage! If it is less than 10CM thick, it is a quality problem.