ON A BALCONY WITH A HEIGHT OF 20M, THROW AN OBJECT HORIZONTALLY WITH AN INITIAL VELOCITY OF 20MS, NO

Updated on Balcony 2024-02-25
4 answers
  1. Anonymous users2024-01-23

    h=1/2gt^2

    t^2=2h/g=2*20/10=4

    t=2sv, vertical 2-v0, 2=2gh

    v Vertical 2 = 2 * 10 * 20 = 400

    Then the combined velocity v= (v vertical 2+v0 2)=20 2 m s

  2. Anonymous users2024-01-22

    Vertical s=1 2gt2 t=2s

    v = gt v (vertical) = 20 m s

    Horizontal v(horizontal) = 20m s

    v = 20 times the root number 2

  3. Anonymous users2024-01-21

    The content of flat throwing motion in the chapter 1 of the 2nd Curve Motion in High School Physics This kind of problem only needs to know that the time of falling in the air is only related to the height difference between the throwing point and the ground, for example, in the problem, it is thrown from a balcony of 20m, then the first question is to use the formula h=1 2gt2 to substitute the data to find the time; After finding the time, the velocity in the vertical direction can be obtained by using v=gt, and then combined with the initial velocity, using the Pythagorean theorem, the combined velocity is obtained. Hope it helps...

  4. Anonymous users2024-01-20

    Needless to say, this is a basic topic of physics in junior high school.

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